2[m-(4m+4)+2]=2(m+2)

Solution for 2[m-(4m+4)+2]=2(m+2) equation:

Simplifying
2[m + -1(4m + 4) + 2] = 2(m + 2)

Reorder the terms:
2[m + -1(4 + 4m) + 2] = 2(m + 2)
2[m + (4 * -1 + 4m * -1) + 2] = 2(m + 2)
2[m + (-4 + -4m) + 2] = 2(m + 2)

Reorder the terms:
2[-4 + 2 + m + -4m] = 2(m + 2)

Combine like terms: -4 + 2 = -2
2[-2 + m + -4m] = 2(m + 2)

Combine like terms: m + -4m = -3m
2[-2 + -3m] = 2(m + 2)
[-2 * 2 + -3m * 2] = 2(m + 2)
[-4 + -6m] = 2(m + 2)

Reorder the terms:
-4 + -6m = 2(2 + m)
-4 + -6m = (2 * 2 + m * 2)
-4 + -6m = (4 + 2m)

Solving
-4 + -6m = 4 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-4 + -6m + -2m = 4 + 2m + -2m

Combine like terms: -6m + -2m = -8m
-4 + -8m = 4 + 2m + -2m

Combine like terms: 2m + -2m = 0
-4 + -8m = 4 + 0
-4 + -8m = 4

Add '4' to each side of the equation.
-4 + 4 + -8m = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8m = 4 + 4
-8m = 4 + 4

Combine like terms: 4 + 4 = 8
-8m = 8

Divide each side by '-8'.
m = -1

Simplifying
m = -1